Integrand size = 25, antiderivative size = 119 \[ \int \cot ^7(c+d x) \csc (c+d x) (a+a \sin (c+d x)) \, dx=\frac {a \csc (c+d x)}{d}-\frac {3 a \csc ^2(c+d x)}{2 d}-\frac {a \csc ^3(c+d x)}{d}+\frac {3 a \csc ^4(c+d x)}{4 d}+\frac {3 a \csc ^5(c+d x)}{5 d}-\frac {a \csc ^6(c+d x)}{6 d}-\frac {a \csc ^7(c+d x)}{7 d}-\frac {a \log (\sin (c+d x))}{d} \]
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Time = 0.06 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {2915, 12, 90} \[ \int \cot ^7(c+d x) \csc (c+d x) (a+a \sin (c+d x)) \, dx=-\frac {a \csc ^7(c+d x)}{7 d}-\frac {a \csc ^6(c+d x)}{6 d}+\frac {3 a \csc ^5(c+d x)}{5 d}+\frac {3 a \csc ^4(c+d x)}{4 d}-\frac {a \csc ^3(c+d x)}{d}-\frac {3 a \csc ^2(c+d x)}{2 d}+\frac {a \csc (c+d x)}{d}-\frac {a \log (\sin (c+d x))}{d} \]
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Rule 12
Rule 90
Rule 2915
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {a^8 (a-x)^3 (a+x)^4}{x^8} \, dx,x,a \sin (c+d x)\right )}{a^7 d} \\ & = \frac {a \text {Subst}\left (\int \frac {(a-x)^3 (a+x)^4}{x^8} \, dx,x,a \sin (c+d x)\right )}{d} \\ & = \frac {a \text {Subst}\left (\int \left (\frac {a^7}{x^8}+\frac {a^6}{x^7}-\frac {3 a^5}{x^6}-\frac {3 a^4}{x^5}+\frac {3 a^3}{x^4}+\frac {3 a^2}{x^3}-\frac {a}{x^2}-\frac {1}{x}\right ) \, dx,x,a \sin (c+d x)\right )}{d} \\ & = \frac {a \csc (c+d x)}{d}-\frac {3 a \csc ^2(c+d x)}{2 d}-\frac {a \csc ^3(c+d x)}{d}+\frac {3 a \csc ^4(c+d x)}{4 d}+\frac {3 a \csc ^5(c+d x)}{5 d}-\frac {a \csc ^6(c+d x)}{6 d}-\frac {a \csc ^7(c+d x)}{7 d}-\frac {a \log (\sin (c+d x))}{d} \\ \end{align*}
Time = 0.26 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.97 \[ \int \cot ^7(c+d x) \csc (c+d x) (a+a \sin (c+d x)) \, dx=\frac {a \csc (c+d x)}{d}-\frac {a \csc ^3(c+d x)}{d}+\frac {3 a \csc ^5(c+d x)}{5 d}-\frac {a \csc ^7(c+d x)}{7 d}-\frac {a \left (6 \cot ^2(c+d x)-3 \cot ^4(c+d x)+2 \cot ^6(c+d x)+12 \log (\cos (c+d x))+12 \log (\tan (c+d x))\right )}{12 d} \]
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Time = 0.32 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.70
method | result | size |
derivativedivides | \(-\frac {a \left (\frac {\left (\csc ^{7}\left (d x +c \right )\right )}{7}+\frac {\left (\csc ^{6}\left (d x +c \right )\right )}{6}-\frac {3 \left (\csc ^{5}\left (d x +c \right )\right )}{5}-\frac {3 \left (\csc ^{4}\left (d x +c \right )\right )}{4}+\csc ^{3}\left (d x +c \right )+\frac {3 \left (\csc ^{2}\left (d x +c \right )\right )}{2}-\csc \left (d x +c \right )-\ln \left (\csc \left (d x +c \right )\right )\right )}{d}\) | \(83\) |
default | \(-\frac {a \left (\frac {\left (\csc ^{7}\left (d x +c \right )\right )}{7}+\frac {\left (\csc ^{6}\left (d x +c \right )\right )}{6}-\frac {3 \left (\csc ^{5}\left (d x +c \right )\right )}{5}-\frac {3 \left (\csc ^{4}\left (d x +c \right )\right )}{4}+\csc ^{3}\left (d x +c \right )+\frac {3 \left (\csc ^{2}\left (d x +c \right )\right )}{2}-\csc \left (d x +c \right )-\ln \left (\csc \left (d x +c \right )\right )\right )}{d}\) | \(83\) |
risch | \(i a x +\frac {2 i a c}{d}+\frac {2 i a \left (105 \,{\mathrm e}^{13 i \left (d x +c \right )}-210 \,{\mathrm e}^{11 i \left (d x +c \right )}-315 i {\mathrm e}^{12 i \left (d x +c \right )}+903 \,{\mathrm e}^{9 i \left (d x +c \right )}+945 i {\mathrm e}^{10 i \left (d x +c \right )}-636 \,{\mathrm e}^{7 i \left (d x +c \right )}-1820 i {\mathrm e}^{8 i \left (d x +c \right )}+903 \,{\mathrm e}^{5 i \left (d x +c \right )}+1820 i {\mathrm e}^{6 i \left (d x +c \right )}-210 \,{\mathrm e}^{3 i \left (d x +c \right )}-945 i {\mathrm e}^{4 i \left (d x +c \right )}+105 \,{\mathrm e}^{i \left (d x +c \right )}+315 i {\mathrm e}^{2 i \left (d x +c \right )}\right )}{105 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{7}}-\frac {a \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}\) | \(203\) |
parallelrisch | \(-\frac {\left (\cot ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )+\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )+\frac {7 \left (\cot ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+\frac {7 \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}-\frac {49 \left (\cot ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-\frac {49 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-28 \left (\cot ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-28 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+49 \left (\cot ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+49 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+203 \left (\cot ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+203 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-245 \cot \left (\frac {d x}{2}+\frac {c}{2}\right )-245 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+896 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )-896 \ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right ) a}{896 d}\) | \(208\) |
norman | \(\frac {-\frac {a}{896 d}-\frac {a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{384 d}+\frac {11 a \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{1120 d}+\frac {11 a \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{384 d}-\frac {7 a \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{160 d}-\frac {25 a \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{128 d}+\frac {7 a \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32 d}+\frac {35 a \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64 d}+\frac {7 a \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32 d}-\frac {25 a \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{128 d}-\frac {7 a \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{160 d}+\frac {11 a \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{384 d}+\frac {11 a \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{1120 d}-\frac {a \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{384 d}-\frac {a \left (\tan ^{16}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{896 d}}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}+\frac {a \ln \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {a \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}\) | \(307\) |
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Time = 0.26 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.45 \[ \int \cot ^7(c+d x) \csc (c+d x) (a+a \sin (c+d x)) \, dx=\frac {420 \, a \cos \left (d x + c\right )^{6} - 840 \, a \cos \left (d x + c\right )^{4} + 672 \, a \cos \left (d x + c\right )^{2} - 420 \, {\left (a \cos \left (d x + c\right )^{6} - 3 \, a \cos \left (d x + c\right )^{4} + 3 \, a \cos \left (d x + c\right )^{2} - a\right )} \log \left (\frac {1}{2} \, \sin \left (d x + c\right )\right ) \sin \left (d x + c\right ) + 35 \, {\left (18 \, a \cos \left (d x + c\right )^{4} - 27 \, a \cos \left (d x + c\right )^{2} + 11 \, a\right )} \sin \left (d x + c\right ) - 192 \, a}{420 \, {\left (d \cos \left (d x + c\right )^{6} - 3 \, d \cos \left (d x + c\right )^{4} + 3 \, d \cos \left (d x + c\right )^{2} - d\right )} \sin \left (d x + c\right )} \]
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Timed out. \[ \int \cot ^7(c+d x) \csc (c+d x) (a+a \sin (c+d x)) \, dx=\text {Timed out} \]
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Time = 0.22 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.79 \[ \int \cot ^7(c+d x) \csc (c+d x) (a+a \sin (c+d x)) \, dx=-\frac {420 \, a \log \left (\sin \left (d x + c\right )\right ) - \frac {420 \, a \sin \left (d x + c\right )^{6} - 630 \, a \sin \left (d x + c\right )^{5} - 420 \, a \sin \left (d x + c\right )^{4} + 315 \, a \sin \left (d x + c\right )^{3} + 252 \, a \sin \left (d x + c\right )^{2} - 70 \, a \sin \left (d x + c\right ) - 60 \, a}{\sin \left (d x + c\right )^{7}}}{420 \, d} \]
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Time = 0.36 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.89 \[ \int \cot ^7(c+d x) \csc (c+d x) (a+a \sin (c+d x)) \, dx=-\frac {420 \, a \log \left ({\left | \sin \left (d x + c\right ) \right |}\right ) - \frac {1089 \, a \sin \left (d x + c\right )^{7} + 420 \, a \sin \left (d x + c\right )^{6} - 630 \, a \sin \left (d x + c\right )^{5} - 420 \, a \sin \left (d x + c\right )^{4} + 315 \, a \sin \left (d x + c\right )^{3} + 252 \, a \sin \left (d x + c\right )^{2} - 70 \, a \sin \left (d x + c\right ) - 60 \, a}{\sin \left (d x + c\right )^{7}}}{420 \, d} \]
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Time = 10.34 (sec) , antiderivative size = 270, normalized size of antiderivative = 2.27 \[ \int \cot ^7(c+d x) \csc (c+d x) (a+a \sin (c+d x)) \, dx=\frac {35\,a\,\mathrm {cot}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{128\,d}+\frac {35\,a\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{128\,d}+\frac {a\,\ln \left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}{d}-\frac {29\,a\,{\mathrm {cot}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{128\,d}-\frac {7\,a\,{\mathrm {cot}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{128\,d}+\frac {a\,{\mathrm {cot}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{32\,d}+\frac {7\,a\,{\mathrm {cot}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{640\,d}-\frac {a\,{\mathrm {cot}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{384\,d}-\frac {a\,{\mathrm {cot}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{896\,d}-\frac {29\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{128\,d}-\frac {7\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{128\,d}+\frac {a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{32\,d}+\frac {7\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{640\,d}-\frac {a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{384\,d}-\frac {a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{896\,d}-\frac {a\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{d} \]
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